AAO Exam-CT 4: Quant (DI - Tabulation)

AAO Exam-CT 4- Quant (DI - Tabulation)

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1. Direction: Study the following table given below carefully and answer the question based on it. These are the marks scored by 4 students in 3 different subjects.

Student name	Physics	Chemistry	Maths
Sumit	70	50	60
Lakshmi	80	60	75
Lakhan	75	90	60
Krishna	50	80	70

Question:

If passing marks is 60% and maximum marks is 100 how many students fail in any one or more subject.

none
one
two
three
four

Solution

According to the given situation passing marks = 60/100 × 100 = 60 marks

There are only 2 students who got less than 60 marks in any of the subject

That is sumit in chemistry and Krishna in physics ∴ there are two students who fail in any of the subject

2. Direction: Study the following table given below carefully and answer the question based on it. These are the marks scored by 4 students in 3 different subjects.

Student name	Physics	Chemistry	Maths
Sumit	70	50	60
Lakshmi	80	60	75
Lakhan	75	90	60
Krishna	50	80	70

Question:

Find out that total marks scored by sumit is how much percent less/more than total marks scored by Krishna?

20%
10%
30%
50%
25%

Solution

Total mark scored by sumit = 70 + 50 + 60 = 180

Total marks scored by Krishna = 50 + 80 + 70 = 200

⇒ required percent = (200 – 180)/200 × 100 = 10%

3. Direction: Study the following table given below carefully and answer the question based on it. These are the marks scored by 4 students in 3 different subjects.

Student name	Physics	Chemistry	Maths
Sumit	70	50	60
Lakshmi	80	60	75
Lakhan	75	90	60
Krishna	50	80	70

Question:

Find out among all the students who got highest marks?

Sumit
Lakshmi
lakhan
Krishna
Can’t be determined

Solution

Marks scored by sumit = 70 + 50 + 60 = 180

Marks scored by Lakshmi = 80 + 60 + 75 = 215

Marks scored by lakhan = 75 + 90 + 60 = 225

Marks scored by Krishna = 50 + 80 + 70 = 200 ⇒ ∴ Highest marks is scored by lakhan.

4. Direction: Study the following table given below carefully and answer the question based on it. These are the marks scored by 4 students in 3 different subjects.

Student name	Physics	Chemistry	Maths
Sumit	70	50	60
Lakshmi	80	60	75
Lakhan	75	90	60
Krishna	50	80	70

Question:

Ratio of marks scored by sumit and Lakshmi together in math to the marks scored by lakhan and Krishna in chemistry together is?

27 : 34
2 : 9
11 : 19
18 : 17
23 : 31

Solution

Marks scored by sumit in maths = 60

Marks scored by lakshmi in maths = 75

marks scored by sumit and Lakshmi together in math = 60 + 75 = 135

mark scored by lakhan in chemistry = 90

marks scored by Krishna in chemistry = 80

marks scored by lakhan and Krishna in chemistry together = 90 + 80 = 170

⇒ required ratio = 135 : 170 ⇒ 27 : 34

5. Direction: Read the following table carefully and answer the following questions.

The following table shows the number of copies sold by five types of Newspapers in urban and rural areas.

	Urban area	Rural area
Indian Express	1000	500
Times of India	2000	1000
Business Standard	2500	1500
Patrika	3000	4000
Dainik Bhaskar	4000	4500

Question:

The number of copies of Indian Express sold in Urban area is approximately what percent more than the number of copies of Indian Express sold in rural area?

25%
15%
20%
100%
10%

Solution

Given:

The number of copies of Indian Express sold in Urban area = 1000

The number of copies of Indian Express sold in Rural area = 500

Calculations:

⇒ Required percentage = (1000 – 500)/500 × 100

⇒ Required percentage = (500)/500 × 100

⇒ Required percentage = 100%

∴ The number of copies of Indian Express sold in Urban areas is 100% more than the number of copies of Indian Express sold in Rural areas.

6. Direction: Read the following table carefully and answer the following questions.

The following table shows the number of copies sold by five types of Newspapers in urban and rural areas.

	Urban area	Rural area
Indian Express	1000	500
Times of India	2000	1000
Business Standard	2500	1500
Patrika	3000	4000
Dainik Bhaskar	4000	4500

Question:

If the ratio of male and female in every Rural area is 3 : 2, Find the number of male who purchased Business Standard and Dainik Bhaskar from Rural areas.

4900
900
1600
2500
3600

Solution

Given:

The ratio of male and female in every Rural area = 3 : 2

Calculation:

Number of males who purchased Business Standard from rural areas = 1500 × 3/5 = 900

Number of males who purchased Dainik Bhaskar from rural areas = 4500 × 3/5 = 2700

Required number of male = 900 + 2700 = 3600

∴ The number of males who purchased Business Standard and Dainik Bhaskar from rural areas is 3600.

7. Direction: Read the following table carefully and answer the following questions.

The following table shows the number of copies sold by five types of Newspapers in urban and rural areas.

	Urban area	Rural area
Indian Express	1000	500
Times of India	2000	1000
Business Standard	2500	1500
Patrika	3000	4000
Dainik Bhaskar	4000	4500

Question:

If the ratio of male and female in every Urban area is 2 : 3, Find the number of females who purchased the Times of India and Patrika from urban areas.

1000
2000
3000
2500
1500

Solution

Given:

The ratio of male and female in every Urban area = 2 : 3

Calculation:

Number of female who purchased Times of India from urban areas = 2000 × 3/5 = 1200

Number of female who purchased Patrika from urban areas = 3000 × 3/5 = 1800

Required number of female = 1800 + 1200 = 3000

∴ The number of female who purchased Times of India and Patrika from urban areas is 3000.

8. Below mentioned table shows usage of Netflix, amazon prime and sony liv over a span of 150 hours in three families. Answer the questions from data mentioned below:

	Netflix	Amazon Prime	Sony Iiv
Family 1	10%	20%	25%
Family 2	45%	10%	25%
Family 3	30%	15%	20%

Question:

Find difference between total number of hours watched on Netflix by all three families and sony liv by all three families.

25 hours
22.5 hours
28 hours
37.5 hours
53 hours

Solution

Calculation:

Total number of hours watched on Netflix by all three families = (0.10 × 150) + (0.45 × 150) + (0.30 × 150)

⇒ (0.10 × 150) + (0.45 × 150) + (0.30 × 150) = 0.85 × 150

⇒ 0.85 × 150 = 127.5 ….(1)

Total number of hours watched on Sony Liv by all three families = (0.25 × 150) + (0.25 × 150) + (0.20 × 150)

⇒ (0.25 × 150) + (0.25 × 150) + (0.20 × 150) = 0.70 × 150 ….(2)

⇒ 0.70 × 150 = 105

Difference = (1) – (2)

⇒ 127.5 – 105

∴ Required difference = 22.5 hours

Hint

Number of hours watched by all families is from 150 hence, add the percentages and then obtain total hours used to reduce the calculation time.

9. Below mentioned table shows usage of Netflix, amazon prime and sony liv over a span of 150 hours in three families. Answer the questions from data mentioned below:

	Netflix	Amazon Prime	Sony Iiv
Family 1	10%	20%	25%
Family 2	45%	10%	25%
Family 3	30%	15%	20%

Question:

Find ratio between total hours watched by family 1 on Netflix and Amazon prime and by family 2 on Amazon prime and sony liv.

3 : 4
5 : 4
6 : 7
7 : 6
4 : 5

Solution

Calculation:

Number of hours watched on Netflix by family 1 = 0.10 × 150

⇒ 0.10 × 150 = 15 ….(1)

Number of hours watched on Amazon prime by family 1 = 0.20 × 150

⇒ 0.20 × 150 = 30 ….(2)

Number of hours watched on Amazon Prime by family 2 = 0.10 × 150

⇒ 0.10 × 150 = 15 ….(3)

Number of hours watched on sony liv by family 2 = 0.25 × 150

⇒ 0.25 × 150 = 37.5 ….(4)

Now, (1) + (2) : (3) + (4)

⇒ (15 + 30) : (15 + 37.5)

⇒ 45 : 52.5

⇒ 9 : 10.5

∴ Required ratio is 6 : 7

Total number of hours watched on Netflix and Amazon prime by family 1 = (0.30) × 150

⇒ 0.30 × 150 = 45 ….(1)

Total number of hours watched on Amazon prime and Sony liv by family 2 = (0.35) × 150

⇒ 0.35 × 150 = 52.5 ….(2)

Now, (1) : (2)

⇒ 45 : 52.5

∴ Required ratio is 6 : 7

10. Below mentioned table shows usage of Netflix, amazon prime and sony liv over a span of 150 hours in three families. Answer the questions from data mentioned below:

	Netflix	Amazon Prime	Sony Iiv
Family 1	10%	20%	25%
Family 2	45%	10%	25%
Family 3	30%	15%	20%

Question:

Find total number of hours watched on Amazon prime and sony liv by family 2 and family 3

105
110
115
120
125

Solution

Calculation:

Number of hours watched on amazon prime by family 2 = 0.10 × 150

⇒ 0.10 × 150 = 15 ….(1)

Number of hours watched on sony liv by family 2 = 0.25 × 150

⇒ 0.25 × 150 = 37.5 ….(2)

Number of hours watched on amazon prime by family 3 = 0.15 × 150

⇒ 0.15 × 150 = 22.5 ….(3)

Number of hours watched on sony liv by family 3 = 0.20 × 150

⇒ 0.20 × 150 = 30 ….(4)

Required answer = (1) + (2) + (3) + (4)

⇒ 15 + 37.5 + 22.5 + 30 = 105

∴ Required answer is 105 hours

Number of hours watched on amazon prime and sony liv by family 2 = (0.10 + 0.25) × 150

⇒ Number of hours watched on amazon prime and sony liv by family 2 = 52.5 ….(1)

Number of hours watched on amazon prime and sony liv by family 3 = (0.15 + 0.20) × 150

⇒ Number of hours watched on amazon prime and sony liv by family 3 = 52.5 ….(2)

Total number of hours asked = (1) + (2)

⇒ 52.5 + 52.5

⇒ required answer = 105

∴ Required answer is 105 hours

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