# AAO Exam-CT 11: Reasoning (Puzzle - Scheduling)

## AAO Exam-CT 11- Reasoning (Puzzle - Scheduling)

0  9 1. Directions: Read the following information carefully and answer the questions given below.

Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.

Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Question:
In which month does Y gave the exam?
• April
• May
• June
• July
• Cannot be determined

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7th and 28th;

1. Only two persons gave after U.

2. Only one person gave between U and S.

From this we get the possible arrangements:

 Months (Days) Date Case I Case II April (30) 7th 28th May (31) 7th 28th S June  (30) 7th 28th U U July (31) 7th 28th S

3. S and R gave on different dates.

4. R gave after S.

From this case II is eliminated as we cannot determine the month in which R gave the exam.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th

5. Five persons gave between W and T.

6. T gave before R and both gave on different dates.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th T T May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th W W

7. Y gave after Z, who gave in the month which has odd number of days.

 Months (Days) Date Case I Case I (a) April (30) 7th X X 28th T T May (31) 7th Z Z 28th S S June  (30) 7th R Y 28th U U July (31) 7th Y R 28th W W

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

 Months (Days) Date Case I (a) April (30) 7th X 28th T May (31) 7th Z 28th S June  (30) 7th Y 28th U July (31) 7th R 28th W

Hence, Y gave the exam in the month of June.

2. Directions: Read the following information carefully and answer the questions given below.

Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.

Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Question:
How many persons gave the exam between X and Z?
• One
• Two
• Three
• Four
• More than four

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7th and 28th;

1. Only two persons gave after U.

2. Only one person gave between U and S.

From this we get the possible arrangements:

 Months (Days) Date Case I Case II April (30) 7th 28th May (31) 7th 28th S June  (30) 7th 28th U U July (31) 7th 28th S

3. S and R gave on different dates.

4. R gave after S.

From this case II is eliminated as we cannot determine the month in which R gave the exam.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th

5. Five persons gave between W and T.

6. T gave before R and both gave on different dates.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th T T May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th W W

7. Y gave after Z, who gave in the month which has odd number of days.

 Months (Days) Date Case I Case I (a) April (30) 7th X X 28th T T May (31) 7th Z Z 28th S S June  (30) 7th R Y 28th U U July (31) 7th Y R 28th W W

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

 Months (Days) Date Case I (a) April (30) 7th X 28th T May (31) 7th Z 28th S June  (30) 7th Y 28th U July (31) 7th R 28th W

Hence, only one person gave the exam between X and Z.

3. Directions: Read the following information carefully and answer the questions given below.

Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.

Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Question:
Four of the following five are alike in a certain way and hence form a group. Find the one who does not belong to that group?
• Z
• R
• Y
• X
• W

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7th and 28th;

1. Only two persons gave after U.

2. Only one person gave between U and S.

From this we get the possible arrangements:

 Months (Days) Date Case I Case II April (30) 7th 28th May (31) 7th 28th S June  (30) 7th 28th U U July (31) 7th 28th S

3. S and R gave on different dates.

4. R gave after S.

From this case II is eliminated as we cannot determine the month in which R gave the exam.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th

5. Five persons gave between W and T.

6. T gave before R and both gave on different dates.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th T T May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th W W

7. Y gave after Z, who gave in the month which has odd number of days.

 Months (Days) Date Case I Case I (a) April (30) 7th X X 28th T T May (31) 7th Z Z 28th S S June  (30) 7th R Y 28th U U July (31) 7th Y R 28th W W

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

 Months (Days) Date Case I (a) April (30) 7th X 28th T May (31) 7th Z 28th S June  (30) 7th Y 28th U July (31) 7th R 28th W

Except W, all other persons gave the exam in odd numbered date.

Hence, W is the odd one out.

4. Directions: Read the following information carefully and answer the questions given below.

Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.

Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Question:
Number of persons who gave the exam before R is the same as the number of persons who gave the exam after ___.
• T
• W
• U
• S
• Z

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7th and 28th;

1. Only two persons gave after U.

2. Only one person gave between U and S.

From this we get the possible arrangements:

 Months (Days) Date Case I Case II April (30) 7th 28th May (31) 7th 28th S June  (30) 7th 28th U U July (31) 7th 28th S

3. S and R gave on different dates.

4. R gave after S.

From this case II is eliminated as we cannot determine the month in which R gave the exam.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th

5. Five persons gave between W and T.

6. T gave before R and both gave on different dates.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th T T May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th W W

7. Y gave after Z, who gave in the month which has odd number of days.

 Months (Days) Date Case I Case I (a) April (30) 7th X X 28th T T May (31) 7th Z Z 28th S S June  (30) 7th R Y 28th U U July (31) 7th Y R 28th W W

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

 Months (Days) Date Case I (a) April (30) 7th X 28th T May (31) 7th Z 28th S June  (30) 7th Y 28th U July (31) 7th R 28th W

Here, the number of persons who gave the exam before R is six similarly the number of persons gave the exam after T is also six.

Hence, T is the correct answer.

5. Directions: Read the following information carefully and answer the questions given below.

Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7th and 28th – of the same year. No two persons gave on the same date of the same month.

Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Question:
On which date and in which month does X gave the exam?
• 28th  May
• 7th April
• 28th April
• 7th July
• 7th May

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7th and 28th;

1. Only two persons gave after U.

2. Only one person gave between U and S.

From this we get the possible arrangements:

 Months (Days) Date Case I Case II April (30) 7th 28th May (31) 7th 28th S June  (30) 7th 28th U U July (31) 7th 28th S

3. S and R gave on different dates.

4. R gave after S.

From this case II is eliminated as we cannot determine the month in which R gave the exam.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th

5. Five persons gave between W and T.

6. T gave before R and both gave on different dates.

 Months (Days) Date Case I Case I (a) April (30) 7th 28th T T May (31) 7th 28th S S June  (30) 7th R 28th U U July (31) 7th R 28th W W

7. Y gave after Z, who gave in the month which has odd number of days.

 Months (Days) Date Case I Case I (a) April (30) 7th X X 28th T T May (31) 7th Z Z 28th S S June  (30) 7th R Y 28th U U July (31) 7th Y R 28th W W

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

 Months (Days) Date Case I (a) April (30) 7th X 28th T May (31) 7th Z 28th S June  (30) 7th Y 28th U July (31) 7th R 28th W

Hence, X gave the exam on 7th in April.

6. Study all the information carefully and answers the following questions given below:

Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.

Question:

How many persons are born between P and S?

• Two
• Three
• Four
• Six
• None of these

From the given statements,

1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence a difference between the age of R and W = 27- 22 = 5 years.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22 W

3) In case-1, As age of S is 33 years born in 1989 and age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who was born in 1984, and age of U is 42 years when born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number.  U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S 1991 31 1993 29 1995 27 R R 1996 26 2000 22 W W

4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born on 1991.

 Year Age Case 1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S T 1991 31 T Q 1993 29 Q 1995 27 R R 1996 26 2000 22 W W

5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-

 Year Age Person 1980 42 U 1984 38 V 1989 33 S 1991 31 T 1993 29 Q 1995 27 R 1996 26 P 2000 22 W

Hence, three persons are born between P and S.

7. Study all the information carefully and answers the following questions given below:

Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.

Question:

What is the age difference between T and R?

• 2
• 4
• 5
• 8
• None of these

From the given statements,

1) The age of R is an odd perfect cube number. As R's age is 27 which is a perfect cube of 3.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22 W

3) In case 1, As age of S is 33 years who born n 1989 and age of U is 42 who born in 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who was born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number.  U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S 1991 31 1993 29 1995 27 R R 1996 26 2000 22 W W

4) T was 2 years older than Q. Hence, in case-1, T was born in 1991, Q was born in 1993 and in case-2, T was born in 1989 and Q was born in 1991.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S T 1991 31 T Q 1993 29 Q 1995 27 R R 1996 26 2000 22 W W

5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-

 Year Age Person 1980 42 U 1984 38 V 1989 33 S 1991 31 T 1993 29 Q 1995 27 R 1996 26 P 2000 22 W

Hence, age difference between T and R is 4 years.

8. Study all the information carefully and answers the following questions given below:

Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.

Question:

Who born just before V?

• S
• T
• U
• R
• None of these

From the given statements,

1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22 W

3) In case-1, As the age of S is 33 years who born on 1989 and the age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case 2, and the age of S is 38 years who born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number.  U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S 1991 31 1993 29 1995 27 R R 1996 26 2000 22 W W

4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born in 1991.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S T 1991 31 T Q 1993 29 Q 1995 27 R R 1996 26 2000 22 W W

5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the give information. Hence in case 1, P was born on 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-

 Year Age Person 1980 42 U 1984 38 V 1989 33 S 1991 31 T 1993 29 Q 1995 27 R 1996 26 P 2000 22 W

Hence, U was born just before V.

9. Study all the information carefully and answers the following questions given below:

Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.

Question:

What is the sum of the ages of W and U?

• 20
• 62
• 60
• 64
• None of these

From the given statements,

1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22 W

3) In case-1, As the age of S is 33 years who born in 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number.  U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S 1991 31 1993 29 1995 27 R R 1996 26 2000 22 W W

4) T was 2 years older than Q. Hence in case-1, T was born on 1991 and Q was born on 1993 and in case-2, T was born on 1989 and Q was born on 1991.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S T 1991 31 T Q 1993 29 Q 1995 27 R R 1996 26 2000 22 W W

5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-

 Year Age Person 1980 42 U 1984 38 V 1989 33 S 1991 31 T 1993 29 Q 1995 27 R 1996 26 P 2000 22 W

Hence, the sum of the ages of W and U = 22 + 42 = 64

10. Study all the information carefully and answers the following questions given below:

Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.

Question:

Four of the following five are alike in a certain way based on their position. Which of the following does not belongs to that group?

• U
• S
• T
• R
• Q

From the given statements,

1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27- 22 = 5 years.

 Year Age Person 1980 42 1984 38 1989 33 1991 31 1993 29 1995 27 R 1996 26 2000 22 W

3) In case-1, As age of S is 33 years who born on 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case-2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born on 1980, hence difference between the age of S and U is 4 which is a perfect square number.  U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S 1991 31 1993 29 1995 27 R R 1996 26 2000 22 W W

4) T was 2 years older than Q. Hence in case-1, T was born in 1991 and Q was born in 1993 and in case-2, T was born in 1989 and Q was born in 1991.

 Year Age Case-1/Person Case-2/ Person 1980 42 U U 1984 38 S 1989 33 S T 1991 31 T Q 1993 29 Q 1995 27 R R 1996 26 2000 22 W W

5) More than three persons were born between P and V, from this condition Case-2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1 , P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be-

 Year Age Person 1980 42 U 1984 38 V 1989 33 S 1991 31 T 1993 29 Q 1995 27 R 1996 26 P 2000 22 W

Hence, Except for U’s age all other persons age is an odd number.

### AAO Exam-CT 12: Reasoning (Puzzle - Double Lineup)       