AAO ExamCT 11: Reasoning (Puzzle  Scheduling)
AAO ExamCT 11 Reasoning (Puzzle  Scheduling)
1. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7^{th} and 28^{th} – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

April

May

July

Cannot be determined
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7^{th} and 28^{th};
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
Months (Days) 
Date 
Case I 
Case II 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 


June (30) 
7^{th} 


28^{th} 
U 
U 

July (31) 
7^{th} 


28^{th} 

S 
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 


5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 
T 
T 

May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 
W 
W 
7. Y gave after Z, who gave in the month which has odd number of days.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 
X 
X 
28^{th} 
T 
T 

May (31) 
7^{th} 
Z 
Z 
28^{th} 
S 
S 

June (30) 
7^{th} 
R 
Y 
28^{th} 
U 
U 

July (31) 
7^{th} 
Y 
R 
28^{th} 
W 
W 
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
Months (Days) 
Date 
Case I (a) 
April (30) 
7^{th} 
X 
28^{th} 
T 

May (31) 
7^{th} 
Z 
28^{th} 
S 

June (30) 
7^{th} 
Y 
28^{th} 
U 

July (31) 
7^{th} 
R 
28^{th} 
W 
Hence, Y gave the exam in the month of June.
2. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7^{th} and 28^{th} – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Two

Three

Four

More than four
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7^{th} and 28^{th};
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
Months (Days) 
Date 
Case I 
Case II 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 


June (30) 
7^{th} 


28^{th} 
U 
U 

July (31) 
7^{th} 


28^{th} 

S 
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 


5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 
T 
T 

May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 
W 
W 
7. Y gave after Z, who gave in the month which has odd number of days.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 
X 
X 
28^{th} 
T 
T 

May (31) 
7^{th} 
Z 
Z 
28^{th} 
S 
S 

June (30) 
7^{th} 
R 
Y 
28^{th} 
U 
U 

July (31) 
7^{th} 
Y 
R 
28^{th} 
W 
W 
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
Months (Days) 
Date 
Case I (a) 
April (30) 
7^{th} 
X 
28^{th} 
T 

May (31) 
7^{th} 
Z 
28^{th} 
S 

June (30) 
7^{th} 
Y 
28^{th} 
U 

July (31) 
7^{th} 
R 
28^{th} 
W 
Hence, only one person gave the exam between X and Z.
3. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7^{th} and 28^{th} – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

Z

R

Y

X
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7^{th} and 28^{th};
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
Months (Days) 
Date 
Case I 
Case II 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 


June (30) 
7^{th} 


28^{th} 
U 
U 

July (31) 
7^{th} 


28^{th} 

S 
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 


5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 
T 
T 

May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 
W 
W 
7. Y gave after Z, who gave in the month which has odd number of days.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 
X 
X 
28^{th} 
T 
T 

May (31) 
7^{th} 
Z 
Z 
28^{th} 
S 
S 

June (30) 
7^{th} 
R 
Y 
28^{th} 
U 
U 

July (31) 
7^{th} 
Y 
R 
28^{th} 
W 
W 
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
Months (Days) 
Date 
Case I (a) 
April (30) 
7^{th} 
X 
28^{th} 
T 

May (31) 
7^{th} 
Z 
28^{th} 
S 

June (30) 
7^{th} 
Y 
28^{th} 
U 

July (31) 
7^{th} 
R 
28^{th} 
W 
Except W, all other persons gave the exam in odd numbered date.
Hence, W is the odd one out.
4. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7^{th} and 28^{th} – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

W

U

S

Z
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7^{th} and 28^{th};
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
Months (Days) 
Date 
Case I 
Case II 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 


June (30) 
7^{th} 


28^{th} 
U 
U 

July (31) 
7^{th} 


28^{th} 

S 
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 


5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 
T 
T 

May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 
W 
W 
7. Y gave after Z, who gave in the month which has odd number of days.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 
X 
X 
28^{th} 
T 
T 

May (31) 
7^{th} 
Z 
Z 
28^{th} 
S 
S 

June (30) 
7^{th} 
R 
Y 
28^{th} 
U 
U 

July (31) 
7^{th} 
Y 
R 
28^{th} 
W 
W 
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
Months (Days) 
Date 
Case I (a) 
April (30) 
7^{th} 
X 
28^{th} 
T 

May (31) 
7^{th} 
Z 
28^{th} 
S 

June (30) 
7^{th} 
Y 
28^{th} 
U 

July (31) 
7^{th} 
R 
28^{th} 
W 
Here, the number of persons who gave the exam before R is six similarly the number of persons gave the exam after T is also six.
Hence, T is the correct answer.
5. Directions: Read the following information carefully and answer the questions given below.
Eight persons – R, S, T, U, W, X, Y and Z – gave the exam in four different months among – April, May, June and July – on different dates among – 7^{th} and 28^{th} – of the same year. No two persons gave on the same date of the same month.
Only two persons gave after U. Only one person gave between U and S. S and R gave exams on different dates. R gave an exam after S. Five persons gave exam between W and T. T gave before R and both gave on different dates. Y gave after Z, who gave in the month which has odd number of days. Y and W did not give in the same month.

28th May

28^{th} April

7th July

7th May
Persons – 8; R, S, T, U, W, X, Y and Z;
Months – April, May, June and July;
Dates – 7^{th} and 28^{th};
1. Only two persons gave after U.
2. Only one person gave between U and S.
From this we get the possible arrangements:
Months (Days) 
Date 
Case I 
Case II 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 


June (30) 
7^{th} 


28^{th} 
U 
U 

July (31) 
7^{th} 


28^{th} 

S 
3. S and R gave on different dates.
4. R gave after S.
From this case II is eliminated as we cannot determine the month in which R gave the exam.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 



May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 


5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 


28^{th} 
T 
T 

May (31) 
7^{th} 


28^{th} 
S 
S 

June (30) 
7^{th} 
R 

28^{th} 
U 
U 

July (31) 
7^{th} 

R 
28^{th} 
W 
W 
7. Y gave after Z, who gave in the month which has odd number of days.
Months (Days) 
Date 
Case I 
Case I (a) 
April (30) 
7^{th} 
X 
X 
28^{th} 
T 
T 

May (31) 
7^{th} 
Z 
Z 
28^{th} 
S 
S 

June (30) 
7^{th} 
R 
Y 
28^{th} 
U 
U 

July (31) 
7^{th} 
Y 
R 
28^{th} 
W 
W 
8. Y and W did not give in the same month.
From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.
Months (Days) 
Date 
Case I (a) 
April (30) 
7^{th} 
X 
28^{th} 
T 

May (31) 
7^{th} 
Z 
28^{th} 
S 

June (30) 
7^{th} 
Y 
28^{th} 
U 

July (31) 
7^{th} 
R 
28^{th} 
W 
Hence, X gave the exam on 7th in April.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
How many persons are born between P and S?

Two

Four

Six

None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence a difference between the age of R and W = 27 22 = 5 years.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 
W 
3) In case1, As age of S is 33 years born in 1989 and age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case2, and the age of S is 38 years who was born in 1984, and age of U is 42 years when born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 

1991 
31 


1993 
29 


1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
4) T was 2 years older than Q. Hence in case1, T was born on 1991 and Q was born on 1993 and in case2, T was born on 1989 and Q was born on 1991.
Year 
Age 
Case 1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 
T 
1991 
31 
T 
Q 
1993 
29 
Q 

1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be
Year 
Age 
Person 
1980 
42 
U 
1984 
38 
V 
1989 
33 
S 
1991 
31 
T 
1993 
29 
Q 
1995 
27 
R 
1996 
26 
P 
2000 
22 
W 
Hence, three persons are born between P and S.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
What is the age difference between T and R?

2

5

8

None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is a perfect cube of 3.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27 22 = 5 years.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 
W 
3) In case 1, As age of S is 33 years who born n 1989 and age of U is 42 who born in 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case2, and the age of S is 38 years who was born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 

1991 
31 


1993 
29 


1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
4) T was 2 years older than Q. Hence, in case1, T was born in 1991, Q was born in 1993 and in case2, T was born in 1989 and Q was born in 1991.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 
T 
1991 
31 
T 
Q 
1993 
29 
Q 

1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be
Year 
Age 
Person 
1980 
42 
U 
1984 
38 
V 
1989 
33 
S 
1991 
31 
T 
1993 
29 
Q 
1995 
27 
R 
1996 
26 
P 
2000 
22 
W 
Hence, age difference between T and R is 4 years.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
Who born just before V?

S

T

R

None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27 22 = 5 years.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 
W 
3) In case1, As the age of S is 33 years who born on 1989 and the age of U is 42 who born on 1980, hence the difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case 2, and the age of S is 38 years who born in 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 

1991 
31 


1993 
29 


1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
4) T was 2 years older than Q. Hence in case1, T was born on 1991 and Q was born on 1993 and in case2, T was born on 1989 and Q was born in 1991.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 
T 
1991 
31 
T 
Q 
1993 
29 
Q 

1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the give information. Hence in case 1, P was born on 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be
Year 
Age 
Person 
1980 
42 
U 
1984 
38 
V 
1989 
33 
S 
1991 
31 
T 
1993 
29 
Q 
1995 
27 
R 
1996 
26 
P 
2000 
22 
W 
Hence, U was born just before V.
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
What is the sum of the ages of W and U?

20

62

60

None of these
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27 22 = 5 years.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 
W 
3) In case1, As the age of S is 33 years who born in 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born in 1980, hence the difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 

1991 
31 


1993 
29 


1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
4) T was 2 years older than Q. Hence in case1, T was born on 1991 and Q was born on 1993 and in case2, T was born on 1989 and Q was born on 1991.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 
T 
1991 
31 
T 
Q 
1993 
29 
Q 

1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
5) More than three persons were born between P and V, from this condition Case 2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1, P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be
Year 
Age 
Person 
1980 
42 
U 
1984 
38 
V 
1989 
33 
S 
1991 
31 
T 
1993 
29 
Q 
1995 
27 
R 
1996 
26 
P 
2000 
22 
W 
Hence, the sum of the ages of W and U = 22 + 42 = 64
Eight Persons P, Q, R, S, T, U, V and W were born in eight different years i.e., 1980, 1984, 1989, 1991, 1993, 1995, 1996 and 2000 but not necessarily in the same order. All calculations are done with respect to the year, 2022 assuming the month and date to be the same as that of the years mentioned above.
The age of R is an odd perfect cube number. Difference between the ages of R and W is 5 years. U is older than S. Difference between the ages of S and U is a perfect square number. The age of S is above 30 years. P is younger than Q. T is 2 years older than Q. More than three persons were born between P and V.
Four of the following five are alike in a certain way based on their position. Which of the following does not belongs to that group?

S

T

R

Q
From the given statements,
1) The age of R is an odd perfect cube number. As R's age is 27 which is perfect cube of 3.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 

2) Difference between the ages of R and W is 5 years. As W's age is 22 hence difference between the age of R and W = 27 22 = 5 years.
Year 
Age 
Person 
1980 
42 

1984 
38 

1989 
33 

1991 
31 

1993 
29 

1995 
27 
R 
1996 
26 

2000 
22 
W 
3) In case1, As age of S is 33 years who born on 1989 and age of U is 42 who born on 1980, hence difference between the age of S and U is 9 which is a perfect square number. The age of S is above 30 years. In case2, and the age of S is 38 years who born on 1984 and age of U is 42 years who born on 1980, hence difference between the age of S and U is 4 which is a perfect square number. U is older than S. Here we get 2 possible cases i.e. Case 1 and Case 2.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 

1991 
31 


1993 
29 


1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
4) T was 2 years older than Q. Hence in case1, T was born in 1991 and Q was born in 1993 and in case2, T was born in 1989 and Q was born in 1991.
Year 
Age 
Case1/Person 
Case2/ Person 
1980 
42 
U 
U 
1984 
38 

S 
1989 
33 
S 
T 
1991 
31 
T 
Q 
1993 
29 
Q 

1995 
27 
R 
R 
1996 
26 


2000 
22 
W 
W 
5) More than three persons were born between P and V, from this condition Case2 is ruled out now because there is no place for P and V in case 2 according to the given information. Hence in case 1 , P was born in 1996 and V was born in 1984, because P is younger than Q. So, the final arrangement will be
Year 
Age 
Person 
1980 
42 
U 
1984 
38 
V 
1989 
33 
S 
1991 
31 
T 
1993 
29 
Q 
1995 
27 
R 
1996 
26 
P 
2000 
22 
W 
Hence, Except for U’s age all other persons age is an odd number.
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